Removing duplicates from a table

2007-05-08 12:21:37 +0000

Let’s assume that you’ve got a table:

```CREATE TABLE #t (
Id INT IDENTITY,
Name VARCHAR(50),
Number INT )```

… into which you’ve accidentally inserted some duplicate rows:

```INSERT INTO #t(Name, Number) VALUES('Alice', 3)
INSERT INTO #t(Name, Number) VALUES('Alice', 3)
INSERT INTO #t(Name, Number) VALUES('Alice', 3)
INSERT INTO #t(Name, Number) VALUES('Alice', 4)
INSERT INTO #t(Name, Number) VALUES('Bob', 1)
INSERT INTO #t(Name, Number) VALUES('Bob', 2)
INSERT INTO #t(Name, Number) VALUES('Bob', 3)
INSERT INTO #t(Name, Number) VALUES('Charlie', 1)
INSERT INTO #t(Name, Number) VALUES('Charlie', 2)
INSERT INTO #t(Name, Number) VALUES('Charlie', 3)
INSERT INTO #t(Name, Number) VALUES('Charlie', 4)
INSERT INTO #t(Name, Number) VALUES('David', 1)
INSERT INTO #t(Name, Number) VALUES('David', 1)
INSERT INTO #t(Name, Number) VALUES('David', 2)
INSERT INTO #t(Name, Number) VALUES('David', 2)```

(The names are those used when discussing crypto.)

As you can see, I’ve managed to insert two duplicate rows for Alice, and two duplicate (but different) rows for David.

It’s pretty easy to find the non-duplicates, by doing the following:

```SELECT MIN(Id) AS Id, Name, Number FROM #t
GROUP BY Name, Number
ORDER BY MIN(Id)```

Actually deleting them, on the other hand, is more tricky:

```DELETE #t FROM
( SELECT MIN(L.Id) AS MinId, L.Name, L.Number FROM #t AS L
INNER JOIN #t AS R
ON L.Name = R.Name AND L.Number = R.Number
AND L.Id <> R.Id
GROUP BY L.Name, L.Number ) AS Q
INNER JOIN #t
ON #t.Id > Q.MinId
AND #t.Name = Q.Name
AND #t.Number = Q.Number```

The inner portion…

```SELECT MIN(L.Id) AS MinId, L.Name, L.Number FROM #t AS L
INNER JOIN #t AS R
ON L.Name = R.Name AND L.Number = R.Number
AND L.Id <> R.Id
GROUP BY L.Name, L.Number```

…selects the first row of each set of duplicates (in no particular order):

```27	David	1
29	David	2
16	Alice	3```

If we join this subquery against the original table, using the greater-than operator…

```SELECT #t.* FROM
( SELECT MIN(L.Id) AS MinId, L.Name, L.Number FROM #t AS L
INNER JOIN #t AS R
ON L.Name = R.Name AND L.Number = R.Number
AND L.Id <> R.Id
GROUP BY L.Name, L.Number ) AS Q
INNER JOIN #t
ON #t.Id > Q.MinId
AND #t.Name = Q.Name
AND #t.Number = Q.Number```

…then we end up with the duplicate rows…

```17	Alice	3
18	Alice	3
28	David	1
30	David	2```

…which we can then delete by changing the SELECT to a DELETE.

Ta-da!